Vector Algebra | Class 12 Maths Chapter 10

πŸ“Œ 1. Introduction to Vectors

A vector is a quantity that has both:

  • Magnitude
  • Direction

Examples:

  • Displacement
  • Velocity
  • Force

πŸ“Š Representation of a Vector

A vector is represented as:a⃗\vec{a}a

Or in component form:aβƒ—=a1i^+a2j^+a3k^\vec{a} = a_1 \hat{i} + a_2 \hat{j} + a_3 \hat{k}a=a1​i^+a2​j^​+a3​k^


aβƒ—=a1i^+a2j^+a3k^\vec{a} = a_1 \hat{i} + a_2 \hat{j} + a_3 \hat{k}a=a1​i^+a2​j^​+a3​k^


πŸ“– 2. Types of Vectors

πŸ”Ή Zero Vector

Magnitude = 0


πŸ”Ή Unit Vector

Magnitude = 1a^=aβƒ—βˆ£aβƒ—βˆ£\hat{a} = \frac{\vec{a}}{|\vec{a}|}a^=∣a∣a​


a^=aβƒ—βˆ£aβƒ—βˆ£\hat{a} = \frac{\vec{a}}{|\vec{a}|}a^=∣a∣a​


πŸ”Ή Equal Vectors

Same magnitude and direction


πŸ”Ή Collinear Vectors

Parallel vectors


πŸ”Ή Coplanar Vectors

Vectors lying in same plane


πŸ“ 3. Magnitude of a Vector

For vector:aβƒ—=a1i^+a2j^+a3k^\vec{a} = a_1 \hat{i} + a_2 \hat{j} + a_3 \hat{k}a=a1​i^+a2​j^​+a3​k^

Magnitude:∣aβƒ—βˆ£=a12+a22+a32|\vec{a}| = \sqrt{a_1^2 + a_2^2 + a_3^2}∣a∣=a12​+a22​+a32​​


∣aβƒ—βˆ£=a12+a22+a32|\vec{a}| = \sqrt{a_1^2 + a_2^2 + a_3^2}∣a∣=a12​+a22​+a32​​


βž• 4. Addition of Vectors

If:aβƒ—=(a1,a2,a3),bβƒ—=(b1,b2,b3)\vec{a} = (a_1, a_2, a_3), \quad \vec{b} = (b_1, b_2, b_3)a=(a1​,a2​,a3​),b=(b1​,b2​,b3​)

Then:aβƒ—+bβƒ—=(a1+b1,a2+b2,a3+b3)\vec{a} + \vec{b} = (a_1 + b_1, a_2 + b_2, a_3 + b_3)a+b=(a1​+b1​,a2​+b2​,a3​+b3​)


πŸ“Œ Properties:

  • Commutative
  • Associative

βž– 5. Subtraction of Vectors

aβƒ—βˆ’bβƒ—=aβƒ—+(βˆ’bβƒ—)\vec{a} – \vec{b} = \vec{a} + (-\vec{b})aβˆ’b=a+(βˆ’b)


βœ–οΈ 6. Scalar Multiplication

If kkk is a scalar:kaβƒ—=(ka1,ka2,ka3)k\vec{a} = (ka_1, ka_2, ka_3)ka=(ka1​,ka2​,ka3​)


πŸ”— 7. Position Vector

Vector representing position of a point from origin.

Example:
Point P(x,y,z)P(x, y, z)P(x,y,z)OPβƒ—=xi^+yj^+zk^\vec{OP} = x\hat{i} + y\hat{j} + z\hat{k}OP=xi^+yj^​+zk^


πŸ“ 8. Section Formula

If point divides line in ratio m:nm:nm:n:rβƒ—=mbβƒ—+naβƒ—m+n\vec{r} = \frac{m\vec{b} + n\vec{a}}{m+n}r=m+nmb+na​


rβƒ—=mbβƒ—+naβƒ—m+n\vec{r} = \frac{m\vec{b} + n\vec{a}}{m+n}r=m+nmb+na​


πŸ“ 9. Dot Product (Scalar Product)

aβƒ—β‹…bβƒ—=∣aβƒ—βˆ£βˆ£bβƒ—βˆ£cos⁑θ\vec{a} \cdot \vec{b} = |\vec{a}| |\vec{b}| \cos \thetaaβ‹…b=∣a∣∣b∣cosΞΈ


aβƒ—β‹…bβƒ—=∣aβƒ—βˆ£βˆ£bβƒ—βˆ£cos⁑θ\vec{a} \cdot \vec{b} = |\vec{a}| |\vec{b}| \cos \thetaaβ‹…b=∣a∣∣b∣cosΞΈ


πŸ“Œ Component Form:

aβƒ—β‹…bβƒ—=a1b1+a2b2+a3b3\vec{a} \cdot \vec{b} = a_1b_1 + a_2b_2 + a_3b_3aβ‹…b=a1​b1​+a2​b2​+a3​b3​


πŸ“Š Properties:

  • Commutative
  • Distributive

πŸ”Ή Angle Between Vectors

cos⁑θ=aβƒ—β‹…bβƒ—βˆ£aβƒ—βˆ£βˆ£bβƒ—βˆ£\cos \theta = \frac{\vec{a} \cdot \vec{b}}{|\vec{a}| |\vec{b}|}cosΞΈ=∣a∣∣b∣aβ‹…b​


cos⁑θ=aβƒ—β‹…bβƒ—βˆ£aβƒ—βˆ£βˆ£bβƒ—βˆ£\cos \theta = \frac{\vec{a} \cdot \vec{b}}{|\vec{a}| |\vec{b}|}cosΞΈ=∣a∣∣b∣aβ‹…b​


πŸ“Œ Special Cases

  • If aβƒ—β‹…bβƒ—=0\vec{a} \cdot \vec{b} = 0aβ‹…b=0 β†’ perpendicular
  • If aβƒ—β‹…bβƒ—>0\vec{a} \cdot \vec{b} > 0aβ‹…b>0 β†’ acute angle

βœ–οΈ 10. Cross Product (Vector Product)

aβƒ—Γ—bβƒ—=∣aβƒ—βˆ£βˆ£bβƒ—βˆ£sin⁑θ n^\vec{a} \times \vec{b} = |\vec{a}| |\vec{b}| \sin \theta \, \hat{n}aΓ—b=∣a∣∣b∣sinΞΈn^


aβƒ—Γ—bβƒ—=∣aβƒ—βˆ£βˆ£bβƒ—βˆ£sin⁑θ n^\vec{a} \times \vec{b} = |\vec{a}| |\vec{b}| \sin \theta \, \hat{n}aΓ—b=∣a∣∣b∣sinΞΈn^


πŸ“Œ Determinant Form:

aβƒ—Γ—bβƒ—=∣i^j^k^a1a2a3b1b2b3∣\vec{a} \times \vec{b} = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \\ a_1 & a_2 & a_3 \\ b_1 & b_2 & b_3 \end{vmatrix}aΓ—b=​i^a1​b1​​j^​a2​b2​​k^a3​b3​​​


πŸ“Š Properties:

  • Not commutative
  • Distributive

πŸ“ Area of Parallelogram

∣aβƒ—Γ—bβƒ—βˆ£|\vec{a} \times \vec{b}|∣aΓ—b∣


πŸ“ Area of Triangle

12∣aβƒ—Γ—bβƒ—βˆ£\frac{1}{2} |\vec{a} \times \vec{b}|21β€‹βˆ£aΓ—b∣


πŸ“Œ 11. Scalar Triple Product

a⃗⋅(b⃗×c⃗)\vec{a} \cdot (\vec{b} \times \vec{c})a⋅(b×c)


πŸ“Š Meaning:

  • Volume of parallelepiped

πŸ“Œ Condition:

If scalar triple product = 0 β†’ vectors are coplanar


πŸ“Œ 12. Vector Triple Product

a⃗×(b⃗×c⃗)\vec{a} \times (\vec{b} \times \vec{c})a×(b×c)


πŸ”Ή Formula:

=bβƒ—(aβƒ—β‹…cβƒ—)βˆ’cβƒ—(aβƒ—β‹…bβƒ—)= \vec{b}(\vec{a} \cdot \vec{c}) – \vec{c}(\vec{a} \cdot \vec{b})=b(aβ‹…c)βˆ’c(aβ‹…b)


aβƒ—Γ—(bβƒ—Γ—cβƒ—)=bβƒ—(aβƒ—β‹…cβƒ—)βˆ’cβƒ—(aβƒ—β‹…bβƒ—)\vec{a} \times (\vec{b} \times \vec{c}) = \vec{b}(\vec{a} \cdot \vec{c}) – \vec{c}(\vec{a} \cdot \vec{b})aΓ—(bΓ—c)=b(aβ‹…c)βˆ’c(aβ‹…b)


πŸ“Š 13. Applications of Vectors

  • Physics (force, velocity)
  • Engineering
  • Computer graphics
  • Navigation
  • 3D geometry

❗ Common Mistakes

  • Confusing dot and cross product
  • Sign errors in determinants
  • Forgetting unit vector
  • Wrong angle calculation

🧠 Exam Tips

  • Practice vector formulas
  • Learn identities
  • Solve NCERT problems
  • Focus on geometry applications

πŸ“š Practice Questions

  1. Find magnitude of vector
  2. Compute dot product
  3. Find angle between vectors
  4. Evaluate cross product

🎯 Conclusion

Vector Algebra is a powerful mathematical tool that simplifies problems involving direction and magnitude. It is essential for understanding advanced topics in mathematics and physics.

Mastering vector operations ensures strong problem-solving skills in exams.

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