Three Dimensional Geometry | Class 12 Maths

πŸ“Œ 1. Introduction

In 3D geometry, every point is represented by three coordinates:(x,y,z)(x, y, z)(x,y,z)

  • xxx β†’ distance along x-axis
  • yyy β†’ distance along y-axis
  • zzz β†’ distance along z-axis

πŸ“– 2. Coordinate Axes and Planes

  • X-axis, Y-axis, Z-axis
  • XY-plane, YZ-plane, ZX-plane

These divide space into 8 octants.


πŸ“ 3. Distance Between Two Points

If points are:P(x1,y1,z1),Q(x2,y2,z2)P(x_1, y_1, z_1), \quad Q(x_2, y_2, z_2)P(x1​,y1​,z1​),Q(x2​,y2​,z2​)

Distance:


PQ=(x2βˆ’x1)2+(y2βˆ’y1)2+(z2βˆ’z1)2PQ = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2 + (z_2-z_1)^2}PQ=(x2β€‹βˆ’x1​)2+(y2β€‹βˆ’y1​)2+(z2β€‹βˆ’z1​)2​


πŸ“Œ 4. Section Formula

If a point divides the line joining two points in ratio m:nm:nm:n:


rβƒ—=mbβƒ—+naβƒ—m+n\vec{r} = \frac{m\vec{b} + n\vec{a}}{m+n}r=m+nmb+na​


rβƒ—=mbβƒ—+naβƒ—m+n\vec{r} = \frac{m\vec{b} + n\vec{a}}{m+n}r=m+nmb+na​


πŸ”Ή Coordinates Form:

x=mx2+nx1m+n,y=my2+ny1m+n,z=mz2+nz1m+nx = \frac{mx_2 + nx_1}{m+n}, \quad y = \frac{my_2 + ny_1}{m+n}, \quad z = \frac{mz_2 + nz_1}{m+n}x=m+nmx2​+nx1​​,y=m+nmy2​+ny1​​,z=m+nmz2​+nz1​​


πŸ“Œ 5. Direction Cosines and Ratios

πŸ”Ή Direction Cosines (l, m, n)

l2+m2+n2=1l^2 + m^2 + n^2 = 1l2+m2+n2=1


l2+m2+n2=1l^2 + m^2 + n^2 = 1l2+m2+n2=1


πŸ”Ή Direction Ratios

Any proportional values to direction cosines.


πŸ“ 6. Equation of a Line in Space


πŸ”Ή Vector Form:

r⃗=a⃗+λb⃗\vec{r} = \vec{a} + \lambda \vec{b}r=a+λb


r⃗=a⃗+λb⃗\vec{r} = \vec{a} + \lambda \vec{b}r=a+λb


πŸ”Ή Cartesian Form:

xβˆ’x1l=yβˆ’y1m=zβˆ’z1n\frac{x – x_1}{l} = \frac{y – y_1}{m} = \frac{z – z_1}{n}lxβˆ’x1​​=myβˆ’y1​​=nzβˆ’z1​​


xβˆ’x1l=yβˆ’y1m=zβˆ’z1n\frac{x – x_1}{l} = \frac{y – y_1}{m} = \frac{z – z_1}{n}lxβˆ’x1​​=myβˆ’y1​​=nzβˆ’z1​​


πŸ“Œ 7. Angle Between Two Lines


cos⁑θ=l1l2+m1m2+n1n2l12+m12+n12β‹…l22+m22+n22\cos \theta = \frac{l_1l_2 + m_1m_2 + n_1n_2}{\sqrt{l_1^2+m_1^2+n_1^2} \cdot \sqrt{l_2^2+m_2^2+n_2^2}}cosΞΈ=l12​+m12​+n12​​⋅l22​+m22​+n22​​l1​l2​+m1​m2​+n1​n2​​


cos⁑θ=l1l2+m1m2+n1n2l12+m12+n12β‹…l22+m22+n22\cos \theta = \frac{l_1l_2 + m_1m_2 + n_1n_2}{\sqrt{l_1^2+m_1^2+n_1^2} \cdot \sqrt{l_2^2+m_2^2+n_2^2}}cosΞΈ=l12​+m12​+n12​​⋅l22​+m22​+n22​​l1​l2​+m1​m2​+n1​n2​​


πŸ“Œ Special Cases

  • If ΞΈ=0∘\theta = 0^\circΞΈ=0∘ β†’ parallel
  • If ΞΈ=90∘\theta = 90^\circΞΈ=90∘ β†’ perpendicular

πŸ“ 8. Shortest Distance Between Two Lines


d=∣(a2βƒ—βˆ’a1βƒ—)β‹…(b1βƒ—Γ—b2βƒ—)∣∣b1βƒ—Γ—b2βƒ—βˆ£d = \frac{|(\vec{a_2} – \vec{a_1}) \cdot (\vec{b_1} \times \vec{b_2})|}{|\vec{b_1} \times \vec{b_2}|}d=∣b1​​×b2β€‹β€‹βˆ£βˆ£(a2β€‹β€‹βˆ’a1​​)β‹…(b1​​×b2​​)βˆ£β€‹


d=∣(a2βƒ—βˆ’a1βƒ—)β‹…(b1βƒ—Γ—b2βƒ—)∣∣b1βƒ—Γ—b2βƒ—βˆ£d = \frac{|(\vec{a_2} – \vec{a_1}) \cdot (\vec{b_1} \times \vec{b_2})|}{|\vec{b_1} \times \vec{b_2}|}d=∣b1​​×b2β€‹β€‹βˆ£βˆ£(a2β€‹β€‹βˆ’a1​​)β‹…(b1​​×b2​​)βˆ£β€‹


πŸ“Œ 9. Equation of a Plane


πŸ”Ή General Form:

ax+by+cz+d=0ax + by + cz + d = 0ax+by+cz+d=0


ax+by+cz+d=0ax + by + cz + d = 0ax+by+cz+d=0


πŸ”Ή Vector Form:

r⃗⋅n⃗=d\vec{r} \cdot \vec{n} = dr⋅n=d


r⃗⋅n⃗=d\vec{r} \cdot \vec{n} = dr⋅n=d


πŸ“ 10. Angle Between Two Planes


cos⁑θ=a1a2+b1b2+c1c2a12+b12+c12β‹…a22+b22+c22\cos \theta = \frac{a_1a_2 + b_1b_2 + c_1c_2}{\sqrt{a_1^2+b_1^2+c_1^2} \cdot \sqrt{a_2^2+b_2^2+c_2^2}}cosΞΈ=a12​+b12​+c12​​⋅a22​+b22​+c22​​a1​a2​+b1​b2​+c1​c2​​


cos⁑θ=a1a2+b1b2+c1c2a12+b12+c12β‹…a22+b22+c22\cos \theta = \frac{a_1a_2 + b_1b_2 + c_1c_2}{\sqrt{a_1^2+b_1^2+c_1^2} \cdot \sqrt{a_2^2+b_2^2+c_2^2}}cosΞΈ=a12​+b12​+c12​​⋅a22​+b22​+c22​​a1​a2​+b1​b2​+c1​c2​​


πŸ“Œ 11. Distance of Point from Plane


d=∣ax1+by1+cz1+d∣a2+b2+c2d = \frac{|ax_1 + by_1 + cz_1 + d|}{\sqrt{a^2 + b^2 + c^2}}d=a2+b2+c2β€‹βˆ£ax1​+by1​+cz1​+dβˆ£β€‹


d=∣ax1+by1+cz1+d∣a2+b2+c2d = \frac{|ax_1 + by_1 + cz_1 + d|}{\sqrt{a^2 + b^2 + c^2}}d=a2+b2+c2β€‹βˆ£ax1​+by1​+cz1​+dβˆ£β€‹


πŸ“Š 12. Applications of 3D Geometry

  • Navigation systems
  • Computer graphics
  • Robotics
  • Architecture
  • Physics

❗ Common Mistakes

  • Sign errors in formulas
  • Confusing direction ratios
  • Mistakes in distance formula
  • Wrong substitution

🧠 Exam Tips

  • Learn all formulas
  • Practice diagrams
  • Solve NCERT problems
  • Focus on vectors

πŸ“š Practice Questions

  1. Find distance between two points
  2. Equation of line
  3. Angle between lines/planes
  4. Shortest distance problems

🎯 Conclusion

Three Dimensional Geometry helps us understand spatial relationships and solve real-world problems involving space. Mastering formulas and concepts is essential for scoring high in exams.

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